How to remove the ‘%20’ from a url in Python?

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0I’m trying to remove with Python (Not C#, PHP or others) the %20 symbol from a url after having transformed it into a string. However the symbol keeps staying unchanged no matter what formatting I tried.here is the code I tried:url = ‘https://www.amazon.com/s?k=hbb%20magic%20dress’ # Type string
title_text_data_file = url.split(‘=’)[1] if ‘%20’in title_text_data_file: title_text_data_file = title_text_data_file.replace(‘%20+’, ”) keyword = title_text_data_file.replace(‘+’, ‘ ‘) title_text_data_file = title_text_data_file + “.txt”print(‘Keyword:’,keyword,’- File title:’,title_text_data_file,’- URL:’,url)Here is what I get:Keyword: hbb%20magic%20dress – File title: hbb%20magic%20dress.txt – URL: https://www.amazon.com/s?k=hbb%20magic%20dressHere is what I would like to get:Keyword: hbb magic dress – File title: hbb+magic+dress.txt – URL: https://www.amazon.com/s?k=hbb%20magic%20dressGuy from bookwormhub.com recomend to solve this problem in this wayActually, it is better to use libraries designed to deal with urls, as that will handle any urlencoded characters, not just spaces (%20). The standard library provides the urllib.parse module.In your case you want to useimport urllib.parse
url = ‘https://www.amazon.com/s?k=hbb%20magic%20dress’ # This extracts the query part from the url query = urllib.parse.urlparse(url).query
# This gets the first k parameter, decoding any urlencoded character, not only spaces(%20) keyword = urllib.parse.parse_qs(query)[‘k’][0]Is this way right?

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